1. Lagrange Theorem:
Order of subgroup H divides order of Group G
Converse false:
having h | g does not imply there exists a subgroup H of order h.
Example: Z3 = {0,1,2} is not subgroup of Z6
although o(Z3)= 3 which divides o(Z6)= 6
However,
if h = p (prime number),
=>
2. Cauchy Theorem: if p | g
then G contains an element x (so a subgroup) of order p.
ie.
$latex x^{p} = e $ ∀x∈ G
3. Sylow Theorem :
for p prime,
if p^n | g
=> G has a subgroup H of order p^n:
$latex h= p^{n}$
Conclusion: h | g
Lagrange (h) => Sylow (h=p^n) => Cauchy (h= p, n=1)
Trick to Remember:
g = kh (god =kind holy)
=> h | g
g : order of group G
h : order of subgroup H of G
k : index
Note:
Prime order Group is cyclic
(Z/pZ, +) order p is cyclic & commutative.
Order 4: Z4 not isomorphic to Z2xZ2
Order 6: only Z6 isomorphic Z2xZ3.
Z6 non-commutative
S3 = {1 2 3} ≈ D3 Not Abelian
(1 2)(1 3) = (1 3 2)
(1 3)(1 2) =(1 2 3)
Lagrange: |G|=6
=> order of subgroups in G = 1,2,3,6
6= 2x3
Cauchy : 2|6, 3|6 (2,3 prime)
=> order of elements in G
= 2, 3
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