For x->0, find limit L of
f(x)= (x³+5x)/x
1) guess L:
f(x)= x(x²+5)/x= x²+5
=> L= 5 when x->0
2) epsilon-delta Proof: find δ in function of ε such that:
|f(x)-5| < ε
|(x²+5)-5| <ε
|x|< √ε
Choose δ=√ε
For all ε, there is δ=√ε such that |x-0|< δ =>|f(x)-5|< ε
If ε=0.5, δ=√0.5=0.25
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